Respuesta :
Answer:
V=34.2 m/s
Explanation:
Given that
Height , h= 54 m
Horizontal distance , x = 35 m
Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.
In vertical direction :
We know that
[tex]V^2_y=U^2_y+2 g h[/tex]
Now by putting the values in the above equation we got
[tex]V^2_y=U^2_y+2 g h[/tex]
[tex]V^2_y=0^2+2\times 9.81 \times 54 [/tex]
Assume [tex]g= 9.81 m/s^2[/tex]
Thus
[tex]V^2_y=1059.48 [/tex]
[tex]V_y=\sqrt{1059.48}\ m/s[/tex]
[tex]V_y=32.54 m/s[/tex]
We also know that
[tex]V_y=U_y+ g\times t[/tex]
[tex]32.54=9.81\times t[/tex]
[tex]t=\dfrac{32.54}{9.81}=3.31\ s[/tex]
In horizontal direction :
[tex]x=U_x\times t[/tex]
[tex]U_x=\dfrac{35}{3.31}=10.54\ m/s[/tex]
Thus the resultant velocity
[tex]V=\sqrt{V^2_y+U^2_x}[/tex]
[tex]V=\sqrt{32.54^2+10.54^2}=34.2\ m/s[/tex]
V=34.2 m/s
Therefore the velocity will be 34.2 m/s.
