Answer:
y=5x-33
Step-by-step explanation:
We are given a point and a slope. Use the slope-intercept formula.
[tex]y-y_{1} =m(x-x_{1} )[/tex]
where (x1, y1) is a point on the line and m is the slope.
The slope is 5 and the point is (5,-8).
x1=5
y1= -8
m=5
[tex]y--8 =5(x-5 )[/tex]
We want to find the equation of the line, which is y=mx+b (m is the slope and b is the y-intercept). Therefore, we must get y by itself on one side of the equation.
[tex]y+8=5(x-5)[/tex]
First, distribute the 5 on the right side of the equation. Multiply each term inside the parentheses by 5.
[tex]y+8=(5*x)+(5*-5)[/tex]
[tex]y+8=5x-25[/tex]
Next, subtract 8 from both sides since it is being added on to y.
[tex]y+8-8=5x-25-8[/tex]
[tex]y=5x-25-8[/tex]
[tex]y=5x-33[/tex]
The equation of the line is: y=5x-33
