Answer:
Moment of inertia of the flywheel is equal to 10.19 kg-m^2
Explanation:
The maximum rotational energy to be stored by the flywheel [tex]E_{r}[/tex] = 2.00 x 10^6 J
Angular speed with which to store this energy ω = 443 rad/s
moment of inertia of the flywheel [tex]I[/tex] = ?
Recall that the energy of a rotating body is gotten from the equation
[tex]E_{r} = Iw^{2}[/tex]
Where [tex]E_{r}[/tex] is the rotational energy of the rotating body
[tex]I[/tex] = moment of inertia of the body
ω = angular speed of the rotating body
imputing the values into the equation, we'll have
2.00 x 10^6 = [tex]I[/tex] x [tex]443^{2}[/tex]
2.00 x 10^6 = [tex]I[/tex] x 196249
[tex]I[/tex] = (2.00 x 10^6) ÷ 196249 = 10.19 kg-m^2
