Answer:
value of Ft(-15,50) = 1.3
Value of Fv(-15,50) = -0.15
Step-by-step explanation:
W = perceived temperature
T = actual temperature
W = f( T,V)
Estimate the values of ft ( -15,50) and fv(-15,50)
calculate the Linear approximation of f at(-15,50)
[tex]f_{t}[/tex] (-15,50) = [tex]\lim_{h \to \o}[/tex] [tex]\frac{f(-15+h,40)-f(-15,40)}{h}[/tex]
from the table take h = 5, -5
[tex]f_{t}(-15,40) = \frac{f(-10,40)-f(-15,40)}{5}[/tex] = [tex]\frac{-21+27}{5} = 1.2[/tex]
[tex]f_{t} = \frac{f(-20,40)-f(-15,40)}{-5}[/tex] = 1.4
therefore the average value of [tex]f_{t} (-15,40) = 1.3[/tex]
This means that when the Temperature is -15⁰c and the 40 km/h the value of Ft (-15,40) = 1.3
calculate the linear approximation of
[tex]f_{v} (-15,40) = \lim_{h \to \o} \frac{f(-15,40+h)-f(-15,40)}{h}[/tex]
from the table take h = 10, -10
[tex]f_{v}(-15,40) = \frac{f(-15,50)-f(-15,40)}{10}[/tex] = [tex]\frac{-29+27}{10} = -0.2[/tex]
[tex]f_{v} (-15,40) = \frac{f(-15,30)-f(-15,40)}{-10}[/tex] = [tex]\frac{-26+27}{-10}[/tex] = -0.1
therefore the average value of [tex]f_{v} (-15,40) = -0.15[/tex]
This means that when the temperature = -15⁰c and the wind speed is 40 km/h the temperature will decrease by 0.15⁰c
w = f(T,v)
= -27 + 1.3(T+15) - 0.15(v-40)
= -27 + 1.3T + 19.5 - 0.15v + 6
= 1.3T - 0.15v -1.5
calculate the linear approximation
[tex]\lim_{v \to \infty}[/tex][tex]\frac{dw}{dv} = \lim_{v \to \infty} \frac{d(1.3T-0.15v-1.5)}{dv}[/tex] = -0.15
