Answer:
The distance between the plane and the observer is 16,659.18ft
Step-by-step explanation:
Complete question:
(An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15,000 ft, what is the distance between the observer and the plane)
Hello,
The question above requires us to find the distance between an observer and a plane. This is very much easy because we are given the angle at which the observer makes with the plane. To solve this question correctly, we need a pictorial representation of the situation.
See attached document for better illustration
In the diagram, we need to find x.
Since the observer and the plane makes a right angled triangle with the distance apart them, we can use SOHCAHTOA
In this case, we have to use Tangent
Tanθ = opposite/ adjacent
θ = 42°
Opposite = 15,000
Adjacent = x
Tan42 = 15000 / x
x = 15000 / tan42
x = 15000 / 0.90
x = 16,659.18ft
The horizontal distance between the observer and the plane is 16,659.18ft
Answer:
I am not too sure but I know it is not 10,035, or 16,648, nor 20,188 because I put that and it wasn’t right so the last option would be.
22,417
