Answer:
2.86 seconds
Step-by-step explanation:
A graphing calculator shows the ball hits the ground at t = 2.86 seconds.
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You can use the quadratic formula with a=-16, b=45, c=2:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-45\pm\sqrt{45^2-4(-16)(2)}}{2(-16)}=\dfrac{45\pm\sqrt{2153}}{32}\approx\{-0.0438,2.8563\}[/tex]
The ball is in the air for about 2.86 seconds.
