HELP!!! Which choice is equivalent to the expression below?
√6+2√3+√27-√12

Answer:
A
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]
Simplifying
[tex]\sqrt{27}[/tex] = [tex]\sqrt{9(3)}[/tex] = [tex]\sqrt{9}[/tex] × [tex]\sqrt{3}[/tex] = 3[tex]\sqrt{3}[/tex]
[tex]\sqrt{12}[/tex] = [tex]\sqrt{4(3)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{3}[/tex] = 2[tex]\sqrt{3}[/tex]
Thus
[tex]\sqrt{6}[/tex] + 2[tex]\sqrt{3}[/tex] + [tex]\sqrt{27}[/tex] - [tex]\sqrt{12}[/tex]
= [tex]\sqrt{6}[/tex] + 2[tex]\sqrt{3}[/tex] + 3[tex]\sqrt{3}[/tex] - 2[tex]\sqrt{3}[/tex] ← collect like terms
= 3[tex]\sqrt{3}[/tex] + [tex]\sqrt{6}[/tex] → A