Respuesta :
Answer:
its D. -3c
Step-by-step explanation:
just took the test
The expression that is equivalent to the expression [(6c² + 3c)/(-4c + 2)] ÷ [(2c + 1)/(4c - 2)] is; -3c
- The fraction we are given to work with is;
[(6c² + 3c)/(-4c + 2)] ÷ [(2c + 1)/(4c - 2)]
- Simplifying the fraction equation by factorization gives:
[3c(2c + 1)/(-2(2c - 1))] ÷ [(2c + 1)/(2(2c - 1)]
- Now, in division of fractions, we know that;
3/2 ÷ 1/5 is the same as; 3/2 × 5/1
Applying this same method to our question gives;
[3c(2c + 1)/(-2(2c - 1))] × [(2(2c - 1)/(2c + 1)]
- 2(2c - 1) is common and will cancel out to get; 3c(2c + 1)/(-1/(2c + 1))
- 2c + 1 is common and will cancel out to get; -3c
Read more about simplification of fractions at;https://brainly.com/question/6109670