Respuesta :

Answer:

[tex] \boxed{\sf \frac{3x}{ {x}^{2} - 4x + 4}} [/tex]

Step-by-step explanation:

[tex] \sf Product \: of \: the \: rational \: expression: \\ \sf \implies \frac{x}{x - 2} \times \frac{3}{x - 2} \\ \\ \sf \implies \frac{3x}{(x - 2)(x - 2)} \\ \\ \sf (x - 2)(x - 2) = (x)(x - 2) - 2(x - 2) : \\ \sf \implies \frac{3x}{ \boxed{ \sf (x)(x - 2) - 2(x - 2)}} \\ \\ \sf (x)(x - 2) - 2(x - 2) = (x)(x) - (2)(x) - 2(x) - (2)( - 2) : \\ \sf \implies \frac{3x}{ \boxed{ \sf (x)(x) - (2)(x) - 2(x) - (2)( - 2) }} \\ \\ \sf \implies \frac{3x}{ \boxed{ \sf {x}^{2}} - 2x - 2x - (2)( - 2)} \\ \\ \sf (2)( - 2) = - 4 : \\ \sf \implies \frac{3x}{ {x}^{2} - 2x - 2x - \boxed{ \sf - 4}} \\ \\ \sf - ( - 4) = 4 : \\ \sf \implies \frac{3x}{ {x}^{2} - 2x - 2x + \boxed{ \sf 4}} \\ \\ \sf - 2x - 2x = - 4x : \\ \\ \sf \implies \frac{3x}{ {x}^{2} - 4x + 4} [/tex]

Step-by-step explanation:

Given,

[tex] \frac{x}{x - 2} \times \frac{3}{x - 2} [/tex]

now, multiplying them we get, 3x/(x-2) (x-2)

or, 3x/x^24x+4 ( (a-b)= a^2-2ab+b^2)

Hope it helps...