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Who'd be better at speed answering? Datguy323 or some Helping Hand? (Not a serious question) Solve for the variables: [tex]x^3+y^7=28\\x^3=27[/tex]

Respuesta :

ujalakhan18

Answer:

x = 3

y = 1

Step-by-step explanation:

The equations are:

[tex]x^3+y^7 = 28[/tex]

and

[tex]x^3 = 27[/tex]

Putting second equation in the first one:

=> [tex]27+y^7 = 28[/tex]

Subtracting 27 to both sides

=> [tex]y^7 = 28-27[/tex]

=> [tex]y^7 = 1[/tex]

Taking power 7 to both sides

=> y = 1

Now,

[tex]x^3 = 27[/tex]

Taking cube root on the both sides

x = 3

DatGuy323

Answer: (3,1)

Step-by-step explanation:

First, to find x, simply take the cube root of 27, or 3.  Thus, x = 3.

Then, simply plug it in:

[tex]27+y^7=28\\Subtract(27)\\y^7=1\\y=1[/tex]

Thus, y = 1

Hope it helps <3

p.s. for some reason, in a graphing calculator, it shows no solutions

Hope it helps <3

2 in a row!

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