Answer:
[tex]\huge \boxed{{x\geq -3, \ x \neq 2}}[/tex]
Step-by-step explanation:
The function is given,
[tex]\displaystyle f(x)=\frac{\sqrt{x+3 }}{(x+8)(x-2)}[/tex]
The domain of a function are all possible values of x.
There are restrictions for the value of x.
The denominator of the function cannot equal 0, if 0 is the divisor then the fraction would be undefined.
[tex]x+8\neq 0[/tex]
Subtract 8 from both parts.
[tex]x\neq -8[/tex]
[tex]x-2\neq 0[/tex]
Add 2 on both parts.
[tex]x\neq 2[/tex]
The square root of x + 3 cannot be a negative number, because the square root of a negative number is undefined. x + 3 has to equal to 0 or be greater than 0.
[tex]x+3\geq 0[/tex]
Subtract 3 from both parts.
[tex]x\geq -3[/tex]
The domain of the function is [tex]x\geq -3[/tex], [tex]x\neq 2[/tex].
