22 points + brainliest! A fair die with sides labeled 1 through 6 is rolled two times. The values of the two rolls are added together. The sum is recorded as the outcome of a single trial of a random experiment. Compute the probability that the sum is 9.

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Answer:

P(9) = 1/9

Step-by-step explanation:

From the contingency table, we see that 9 appears 4 times out of the 36 possible outcomes, therefore the probability of having a sum of 9 is

P(9) = 4/36 = 1/9

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The probability that the sum is 9 is 1/18.

What is probability?

The probability is defined as the possibility of an event is equal to the ratio of the number of favorable outcomes and the total number of outcomes.

The sample space of rolling two dice has 36 possible outcomes.  

Remember that the sample space is a set that contains all possible outcomes.  

(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)

(1,2) (2,2) (3,2) (4,2) (5,2) (6,2)

(1,3) (2,3) (3,3) (4,3) (5,3) (6,3)

(1,4) (2,4) (3,4) (4,4) (5,4) (6,4)

(1,5) (2,5) (3,5) (4,5) (5,5) (6,5)

(1,6) (2,6) (3,6) (4,6) (5,6) (6,6)

Let E = the event of getting a sum of that number is 9

favorable outcomes = (5,4) (4,5)

So, n(E) = 2

Sample space n(S) = 36

p(E) = n(E)/n(S)

p(E) = 2/36

p(E) = 1/18

Hence, the probability that the sum is 9 is 1/18.

Learn more about probability here:

brainly.com/question/11234923

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