Answer:
(c) 82%
Explanation:
Using the chemical reaction:
3CH₃OH + 4MnO₄⁻ → 3HCOOH + 4MnO₂ + 4e⁻
3 moles of methanol produce 3 moles of formic acid (Reaction 1:1)
To find the percent yield we need to calculate theoretical yield of the reaction when 12g of methanol (Molar mass: 32.04g/mol) are reacting, thus:
12g ₓ (1mol / 32.04g) = 0.3745 moles of methanol are in 12g.
As 1 mole of methanol produce 1 mole of formic acid, assuming a 100% of yield in the reaction (Theoretical yield) moles produced of formic acid are 0.3745 moles.
Using molar mass of formic acid (46.03g/mol), mass of the acid in 0.3745moles are:
0.3745 moles ₓ (46.03g/mol) = 17.2g of formic acid are theoretical yield
Percent yield is calculated as:
(actual yield / Theoretical yield) × 100
As actual yield of the reaction is 14g. Theoretical yield is:
(14g / 17.2g) × 100 = 81.2% ≈ 82%
Right answer is:
The percentage yield of the reaction is 82%
The correct answer to the question is Option C. 82%
We'll begin by writing the balanced equation for the reaction.
3CH₃OH + 4MnO₄⁻ → 3HCOOH + 4MnO₂ + 4e⁻
Molar mass of CH₃OH = 12 + (3×1) + 16 + 1 = 32 g/mol
Mass of CH₃OH from the balanced equation = 3 × 32 = 96 g
Molar mass of HCOOH = 1 + 12 + 16 + 16 + 1 = 46 g/mol
Mass of HCOOH from the balanced equation = 3 × 46 = 138 g
From the balanced equation above,
96 g of CH₃OH reacted to produce 138 g of HCOOH
From the balanced equation above,
96 g of CH₃OH reacted to produce 138 g of HCOOH.
Therefore,
12 g of CH₃OH will react to produce = (12 × 138)/96 ≈ 17g of HCOOH.
Actual yield of HCOOH = 14 g
Theoretical yield of HCOOH = 17 g
Percentage yield = Actual / Theoretical × 100
Percentage yield = 14/17 × 100
The correct answer to the question is Option C. 82%
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