Answer:
The moment of inertial of the wheel, [tex]I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2[/tex]
Explanation:
Given;
8 spokes of uniform diameter
mass of each spoke, = [tex]M_s[/tex]
length of each spoke, = L
mass of outer ring, = [tex]M_r[/tex]
The moment of inertial of the wheel will be calculated as;
[tex]I = 8I_{spoke} + I_{ring}[/tex]
where;
[tex]I_{spoke[/tex] is the moment of inertia of each spoke
[tex]I_{ring[/tex] is the moment of inertia of the rim
Moment of inertia of each spoke [tex]=\frac{1}{3}M_sL^2[/tex]
Moment of inertial of the wheel
[tex]I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2[/tex]
