Respuesta :
Answer:
The steady force required of each rocket is 31.36 N
Explanation:
Given that,
Mass of satellite = 3600 Kg
Radius = 4 m
Mass of rocket = 250 kg
Time = 5 min
Angular velocity = 32 rpm
We need to calculate the moment of inertia
Using formula of moment of inertia
[tex]I=\dfrac{1}{2}Mr^2+4mr^2[/tex]
Where, M = mass of satellite
r = radius
m = mass of rocket
Put the value into the formula
[tex]I=\dfrac{1}{2}\times3600\times4^2+4\times250\times4^2[/tex]
[tex]I=44800\ kg-m^2[/tex]
We need to calculate the angular acceleration
Using formula of angular acceleration
[tex]\alpha=\dfrac{\omega}{t}[/tex]
Where, [tex]\omega[/tex] = angular velocity
t = time
Put the value into the formula
[tex]\alpha=\dfrac{2\pi\times32}{3600\times5}[/tex]
[tex]\alpha=0.0112\ rad/s^2[/tex]
We need to calculate the steady force required of each rocket
Using formula of torque
[tex]\tau=I\alpha[/tex]
[tex]4rF=I\alpha[/tex]
[tex]F=\dfrac{I\alpha}{4r}[/tex]
Put the value into the formula
[tex]F=\dfrac{44800\times0.0112}{4\times4}[/tex]
[tex]F=31.36\ N[/tex]
Hence, The steady force required of each rocket is 31.36 N
The steady force required of each rocket is = 31.36 N
Given data:
mass of satellite ( M ) = 3600 kg
radius of satellite ( r ) = 4 m
mass added by each rocket ( m ) = 250 kg
Angular speed of satellite = 32 rpm
Time = 5 mins
First step : Calculate the value of the moment of inertia
I = [tex]\frac{1}{2} Mr^2 + 4mr^2[/tex] ----- ( 1 )
where : M = 3600 kg, m = 250 kg, r = 4m.
Insert values into equation ( 1 )
I = 44800 kg-m^2
Next step : Determine the angular acceleration
∝ = ω / t
= ( 2π * 32 ) / 3600 * 5
= 0.0112 rad/s²
Final step : Determine the steady force required by each rocket
Τ = I * ∝ ----- ( 1 )
where T = 4rF
Equation ( 1 ) becomes
4rF = I * ∝
∴ F = I*∝ / 4r
= ( 44800 * 0.0112 ) / 4*4
= 31.36 N .
Hence we can conclude that The steady force required of each rocket is = 31.36 N
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