Which of the following would NOT be a conversion factor for mole to mole calculations for the following reaction: 2Al + 3Cl2 --> 2AlCl3
A: 3 mol Cl2 3 mol Al
B: 2 mol Al 3 mol Cl2
C: 2 mol AlCl3 2 mol Al
D: 3 mole Cl2 2 mol AlCl3

Respuesta :

Answer: A. 3 mol [tex]Cl_2[/tex] 3 mol Al:

Explanation:

Te given balanced chemical equation is :

[tex]2Al+3Cl_2\rightarrow 2AlCl_3[/tex]

According to the stochiometry :

A: 3 mol [tex]Cl_2[/tex] 3 mol Al:

3 moles of chlorine reacts with 2 moles of aluminium

B. 2 mol [tex]Al[/tex] 3 mol [tex]Cl_2[/tex]:

2 moles of aluminium  reacts with 3 moles of chlorine

C.  2 mol [tex]AlCl_3[/tex] 2 mol Al

2 mol of aluminium produces 2 mol of [tex]AlCl_3[/tex]

D. 3 mol [tex]Cl_2[/tex] 2 mol [tex]AlCl_3[/tex]

3 moles of chlorine produces with 2 moles of [tex]AlCl_3[/tex]

Thus the conversion factor not used for mole to mole calculations is  3 mol [tex]Cl_2[/tex] 3 mol Al: