g(x)= √x+3 help plsss

Answer:
All real values of x such that x ≥-3
Step-by-step explanation:
g(x) = sqrt(x+3)
A sqrt must be greater than or equal to zero
sqrt (x+3) ≥ 0
Square each side
x+3≥ 0
Subtract 3 from each side
x ≥-3
The restrictions on x are x ≥-3
That means the domain is x ≥-3
All real values of x such that x ≥-3
Answer:
[tex]\boxed{\mathrm{B}}[/tex]
Step-by-step explanation:
[tex]g(x)=\sqrt{x+3}[/tex]
A square root must have a value of greater than or equal to 0.
[tex]\sqrt{x+3}\geq 0[/tex]
Square both sides.
[tex]x+3\geq 0[/tex]
Subtract 3 from both sides.
[tex]x\geq -3[/tex]