Answer:
The magnetic flux is [tex]\phi = 15 \ Nm^2 /C[/tex]
Explanation:
From the question we are told that
The value of the charge is [tex]q = 0.80 \ nC = 0.80 *10^{-9} \ C[/tex]
The length of each side of the cube is [tex]d = 4.0 \ m[/tex]
Generally the magnetic flux through a closed surface is mathematically represented as
[tex]\phi = \frac{q}{\epsilon_o} * D[/tex]
Where D is the area enclosing the charge
Now a cube is made up of six faces but in this question we are considering only one face which is mathematically represented as
[tex]D = \frac{1}{6}[/tex]
So the electric flux through one face of the cube is mathematically represented as
[tex]\phi = \frac{q}{6 * \epsilon _o }[/tex]
where [tex]\epsilon _o[/tex] is the permitivity of free space with value
[tex]\epsilon_o = 8.85 *10^{-12} F/m[/tex]
substituting value
[tex]\phi = \frac{0.80 *10^{-9}}{6 * 8.85 *10^{-12} }[/tex]
[tex]\phi = 15 \ Nm^2 /C[/tex]
