Find the value of x in the
isosceles triangle shown below.
Help plzzzz

Answer:
x =2
Option D is correct !!!
Step-by-step explanation:
By Pythagoras theorem we can solve this
we know that:
[tex] {x}^{2} + {4}^{2} = \sqrt{20} {}^{2} [/tex]
[tex] {x}^{2} = \sqrt{20} ^{2} - 16[/tex]
[tex]{x}^{2} = 20 - 16[/tex]
[tex]x = 2[/tex]