What is the solution to the system of equations graphed below?

Answer:
Option B is the correct option.
Step-by-step explanation:
[tex]y = - 2x + 4...........(i)[/tex]
[tex]y = x - 5..........(ii)[/tex]
Equate ( i ) and ( ii ),
[tex] - 2x + 4 = x - 5[/tex]
Move variable to L.H.S and change its sign
Similarly, Move constant to R.H.S and change its sign
[tex] - 2x - x = - 5 - 4[/tex]
Calculate
[tex] - 3x = - 9[/tex]
Divide both sides of the equation by -3
[tex] \frac{ - 3x}{ - 3} = \frac{ - 9}{ - 3} [/tex]
Any expression divided by itself equals 1
[tex]x = \frac{ - 9}{ - 3} [/tex]
Dividing two negatives equals a positive [tex]( - ) \div ( - ) = ( + )[/tex]
[tex]x = \frac{9}{3} [/tex]
calculate the quotient
[tex]x = 3[/tex]
Value of X is 3
Now, put the value of X in equation ( i ) in order to find the value of y
[tex]y = x - 5[/tex]
plug the value of X
[tex] = 3 - 5[/tex]
Calculate
[tex] = - 2[/tex]
Value of y is -2
So, ( 3 , -2 ) is the solution of the given equation.
Hope this helps ....
Best regards!!