Answer:
The completed table is
x | 0 | 6 | 12
y | 0 | 2 | 4
Step-by-step explanation:
It is given that y is (1/3) as large as x. That is,
y = (x/3)
x | 0 | 6 | 12
y | ? | ? | ?
y = (x/3)
When x = 0,
y = (0/3) = 0
when x = 6,
y = (6/3) = 2
when x = 12,
y = (12/3) = 4
The completed table is thus
x | 0 | 6 | 12
y | 0 | 2 | 4
Hope this Helps!!!
The values of x will be 0 , 18 , 36 respectively when the value of y is 0, 6, 12.
Given,
y is 1/3 times as large as x.
So, [tex]x=3y[/tex].
We have to calculate the value of x when y is given .
1. when [tex]y=0[/tex]
Then, [tex]x=0[/tex]
2.when, [tex]y=6[/tex]
Then, [tex]x=18\\[/tex]
3. When [tex]y=12[/tex]
[tex]x=3\times 12\\x=36[/tex]
Hence, the values of x will be 0 , 18 , 36 respectively when the value of y is 0, 6, 12.
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https://brainly.com/question/11897796
