Answer:
Step-by-step explanation:
When the stick is placed along the diagonal of the cuboid , shortest possible length will extend out above top of the crate .
Length of the diagonal
= [tex]\sqrt{36^2+36^2+60^2}[/tex]
= 78.69 cm
the length of the stick that extends out of the crate
= 90 - 78.69
= 11.31 cm
If θ be the angle made by stick with the base
cosθ = hypotenuse of base / diagonal of cuboid
=[tex]\frac{\sqrt{2}\times36 }{78.69}[/tex]
= [tex]\frac{50.90 }{78.69}[/tex]
θ = 50°
Answer: This is the answer to B) 47.9 degrees
Step-by-step explanation:
Pythagoras: a^2+b^2=c^2
36²+36²=C²
√2592=C
C=50.9cm
Used Trigonometry: SOH CAH TOA
Tan=Opposite/Adjacent
Tan=60/50.9
The angle stick makes when it meets the base:
Tan^-1(60/50.9)
=49.7˚
