Answer:
It is an example of elimination reaction through the E2 mechanism.
Explanation:
The reaction between 1-iodobutane and pyridine is an example of an E2 (bimolecular elimination) elimination reaction.
Pyridine acts predominantly as a base and the given alkyl halide is a primary alkyl halide. Both of these two factors facilitate the E2 mechanism.
Here, both H and Cl are eliminated in a single step to produce 1-butene as the product of the reaction.
The reaction mechanism and the structure of the product are shown below.
The mechanism by which 1-iodobutane reacts with pyridine is by the E2 mechanism.
The E2 mechanism process (Bimolecular Elimination) is a one-step reaction mechanism whereby carbon-hydrogen (C-H) and carbon-halogen (C-X) bonds split to generate a double bond. (C = C πbond).
The following characteristics of the E2 reaction are:
From the information given:
Pyridine functions primarily as a base, and the alkyl iodide in question is a primary alkyl halide that helps in the E2 mechanism.
In this case, both H and Cl are removed in a single step, yielding 1-butene as the byproduct of the reaction.
Learn more about the Bimolecular Elimination reaction here:
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