Respuesta :
Answer:
For this case we know that at the starting year 2000 the population was 9 billion and we also know that increasing with a double time of 20 years so we can set up the following model:
[tex]18 =9(b)^20[/tex]
And if we solve for b we got:
[tex] 2 = b^20[/tex]
[tex]2^{1/20}= b[/tex]
And then the model would be:
[tex] y(t) = 9 (2)^{\frac{t}{20}}[/tex]
Where y is on billions and t the time in years since 2000.
And for this equation is possible to find the population any year after 2000
Step-by-step explanation:
For this case we know that at the starting year 2000 the population was 9 billion and we also know that increasing with a double time of 20 years so we can set up the following model:
[tex]18 =9(b)^20[/tex]
And if we solve for b we got:
[tex] 2 = b^20[/tex]
[tex]2^{1/20}= b[/tex]
And then the model would be:
[tex] y(t) = 9 (2)^{\frac{t}{20}}[/tex]
Where y is on billions and t the time in years since 2000.
And for this equation is possible to find the population any year after 2000
