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According to Hooke's Law, the force needed to stretch a spring varies directly to the amount the spring is stretched. If 50 pounds of force stretches a spring five inches, how much will the spring be stretched by a force of 180 pounds? inches

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boffeemadrid

The length a spring stretches when subjected to the given load is required.

The spring is stretched by 18 inches.

Hooke's law

F = Force

k = Spring constant

x = Stretched length

[tex]F=50\ \text{lbf}[/tex]

[tex]x=5\ \text{inch}[/tex]

Hooke's law is given by

[tex]F=kx\\\Rightarrow 50=k5\\\Rightarrow k=\dfrac{50}{5}\\\Rightarrow k=10\ \text{lbf/inch}[/tex]

[tex]F=180\ \text{lbf}[/tex]

For the required spring

[tex]F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{180}{10}\\\Rightarrow x=18\ \text{inches}[/tex]

Learn more about Hooke's law:

https://brainly.com/question/2648431

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