A particular brand of gasoline has a density of 0.737 g/mL at 25 ∘C. How many grams of this gasoline would fill a 13.6 gal tank (1US gal=3.78L)? Express your answer to three significant figures and include the appropriate units.

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Muscardinus Muscardinus · Answer 1 · 2020-08-27T09:59:49+02:00

Answer:

Mass, m = 37900 grams

Explanation:

Given that,

The density of a brand of gasoline is 0.737 g/mL at 25°C

We need to find mass of gasoline would fill a 13.6 gal tank.

Density is defined as mass per unit volume.

We know that, 1US gal=3.78L

So,

1US gal = 3785.41 mL

13.6 US gal = 51481.6 mL

So,

[tex]d=\dfrac{m}{V}\\\\m=d\times V\\\\m=0.737\ g/mL\times 51481.6\ mL\\\\m=37941.93\ g[/tex]

or

m = 37900 g (in three significant figures)

So, the mass of the gasoline is 37900 grams.

virtuematane virtuematane · Answer 2 · 2022-01-14T11:41:51+01:00

Mass, m = 37900 grams

Given that,

The density of a brand of gasoline is 0.737 g/mL at 25°C

find the mass of gasoline would fill a 13.6 gal tank.

Density is defined as mass per unit volume.

We know that, 1US gal=3.78L

So,

1US gal = 3785.41 mL

13.6 US gal = 51481.6 mL

So,

[tex]Density=\frac{mass}{volume}\\\\0.737\ g/mL=mass/51481.6\ mL\\mass=37941.9392\ g[/tex]

or

m = 37900 g (in three significant figures)

So, the mass of the gasoline is 37900 grams.

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