Answer:
62.8 m
Step-by-step explanation:
The length of one lap is ...
C = 2πr = 2π(25 m) = 50π m ≈ 157.08 m
Sarah is gaining ground on John at the rate of 2.7 m/s -2.2 m/s = 0.5 m/s. So it will take Sarah ...
157.08 m/(0.5 m/s) = 314.16 s
to run 1 lap farther than John does.
It takes Sarah ...
157.08 m/(2.7 m/s) = 58.18 s
to run 1 lap, so in the time it takes her to catch John, she will have run ...
314.16 s/(58.18 s/lap) = 5.4 laps
She (and John) will be 0.4 laps from their start when they meet again. That distance is ...
(0.4)(157.08 m) = 62.8 m
Sarah will catch and pass John 62.8 meters from their starting position.