Answer:
c) 0.10M NaCl
Explanation:
Options are:
a) 0.20M NaCl
b) Very acidic
c) 0.10M NaCl
d) 0.10M HCl + 0.20M NaOH
e) Slightly acidic.
Based on the reaction:
NaOH + HCl → H₂O + NaCl
You can see than 1 mole of NaOH reacts per mole of HCl producing 1 mole of NaCl
Assuming 1L of 0.20M HCl reacts with 1L of NaOH, moles of both compounds are:
1L * 0.20mol/L = 0.20 moles reacts. That means moles of NaCl produced are 0.20moles in 2L. Molarity of NaCl is:
0.20mol / 2L = 0.10M NaCl
That means, right option is:
At the equivalence point, 0.01 M NaCl is present.
The reaction between NaOH and HCl occurs as follows;
NaOH(aq) + HCl(aq) ------> NaCl(aq) + H2O(l)
Concentration of HCl = 0.20 M
Concentration of NaOH = 0.20 M
Let as assume that the volume of both solutions is 1 L each
Number of moles of HCl = 0.20 moles
Number of moles of NaOH = 0.20 moles
The reaction is 1:1 hence 0.20 moles of NaCl is formed. However, the volume of the solution is now 2L.
Concentration of NaCl = 0.20 moles/2L = 0.01 M
Missing parts;
In titrating 0.20 M hydrochloric acid, HCl, with 0.20 M NaOH at 25°C, the solution at the equivalence point is
Select one:
a. 0.20 M NaCl
b. very acidic
c. slightly acidic
d. 0.10 M HCl and 0.20 M NaOH
e. 0.10 M NaCl
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