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A car rolls down a ramp in a parking garage. The horizontal position of the car in meters over time is shown below. Graph of horizontal position x (in meters) on y axis and time (in seconds) on x axis. The initial position is -3 m at t=0 s, and the position increases linearly to 3 m at t=8 s. Then the position is constant at 3 m until t=16 s, then increases linearly to 9 m at t=24 s.

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Answer:

Explanation:

At t = 0 , X = -3 m

At t = 8s  , X = + 3 m .

At t = 16s  , X = + 3 m

At t = 24 s , X = + 9 m

Graph is shown in the attached file .

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onyebuchinnaji

The displacement of the car between 8 seconds and 24 seconds is 6 m.

The given parameters:

  • Initial position of the car, x₁ = -3 m, time = 0 s
  • Second displacement, x₂ = 3 m, time = 8.0 s
  • Third displacement, x₃ = 3 m, time = 16 s
  • Final displacement, x₄ = 9 m, time = 24 s

The displacement of the car between 8 seconds and 24 seconds is calculated as follows;

the position of the car at 8 seconds = 3 m

the position of the car at 24 seconds = 9 m

The displacement of the car = 9m - 3m = 6 m

Thus, the displacement of the car between 8 seconds and 24 seconds is 6 m.

The complete question is below:

What would be the displacement of the car between eight seconds and 24 seconds?

Learn more about displacement here: https://brainly.com/question/2109763

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