A weight of 35.0 N is suspended from a spring that has a force constant of 220 N/m. The system is undamped and is subjected to a harmonic driving force of frequency 10.5 Hz, resulting in a forced-motion amplitude of 3.00 cm. Determine the maximum value of the driving force.

Respuesta :

Answer:

The force is  [tex]F = 423.04 \ N[/tex]

Explanation:

From the question we are told that

   The weight is  [tex]W = 35 .0 \ N[/tex]

    The  force constant is  [tex]k = 220 \ N/m[/tex]

    The frequency is  [tex]f = 10.5 \ Hz[/tex]

     The amplitude is  [tex]A = 3.00 \ cm = 0.03 \ m[/tex]

Generally the maximum driving force is mathematically represented as

     [tex]F = m * w^2 A[/tex]

Here  m is the mass of the weight which is  mathematically represented as  

       [tex]m = \frac{ W }{g}[/tex]

=>     [tex]m = \frac{ 35 }{9.8 }[/tex]

=>     [tex]m = 3.571 \ kg[/tex]

  Also   [tex]w[/tex] is the angular frequency of the weight which is mathematically represented as

         [tex]w = 2 \pi * f[/tex]

         [tex]w = 2* 3.142 * 10[/tex]

=>      [tex]w = 62.84 \ rad/s[/tex]

So

    [tex]F = 3.571 * 62.84^2 * 0.03[/tex]

    [tex]F = 423.04 \ N[/tex]