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As stated in the statement of the question, EF is a bisector of CD, so point G is the median point of CD, so CG = GD
5X - 1 = 7X - 13
X = 6
EF = EG + GF
6X - 4 = EG + 13 x = 6, so
6·6 - 4 = EG + 13
(see attachment)
A line segment is also a line but the line with finite length and having fixed endpoints. The length of the line segment EG is 19 unit.
A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely.
Given that EF bisects CD at point G, therefore, the line segment CD will be divided into two equal parts, CG and GD. Therefore, we can write,
CG = GD
5x - 1 = 7x - 13
-1 + 13 = 7x - 5x
12 = 2x
x = 12/2
x = 6
Further, the length of segment EG will be,
EG = EF - GF
= 6x - 4 - (13)
= 6x - 4 - 13
= 6x - 17
= 6(6) - 17
= 36 - 17
= 19
Hence, the length of the line segment EG is 19 unit.
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