Respuesta :
Answer:
A: Linear
B: Linear
C: Linear
Step-by-step explanation:
So we have three functions:
[tex]f(x)=3x+1\\f(x)=x-6x+5\\f(x)=4x-x+1[/tex]
To determine the type of graph for each function, simplify each of them and then we can determine whether it's linear or quadratic.
1)
We have:
[tex]f(x)=3x+1[/tex]
This has a degree of 1. Quadratics have a degree of 2. In other words, quadratics have a x^2 term. There isn't one here, so this is a linear equation.
2)
We have:
[tex]f(x)=x-6x+5[/tex]
Simplify:
[tex]f(x)=-5x+5[/tex]
Again, this is of degree 1. There is no x^2 term. Thus, this is also a linear equation.
3)
We have:
[tex]f(x)=4x-x+1[/tex]
Simplify:
[tex]f(x)=3x+1[/tex]
This has a degree of 1. There is no x^2 term. Thus, this is also a linear equation.
Answer:
Step-by-step explanation:
a- f(x)=3x+1 it is linear equation
b: f(x)=x-6x+5
f(x)=-5x+5 linear equation
c: f(x)=4x-x+1
f(x)=3x+1 (linear equation)
(if there is no exponent then the graph is linear)
