Answer:
y= 3(x-1)^2+2
Step-by-step explanation:
The vertex form for h(x)= -3x^2-6x+5 is y= 3(x-1)^2+2.
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The equation of the parabola h(x) = –3x² – 6x + 5 in the vertex form can be written as y = -3(x-1)²+8.
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.
The vertex form of a quadratic equation is given as y = a(x-h)² + k, where h and k are the x and y coordinates of the vertex of the parabola.
Given the equation of the parabola, h(x) = –3x² – 6x + 5. Comparing the given equation with the general quadratic equation, the value of the variables a, b, and c can be written as shown.
ax² + bx + c
–3x² – 6x + 5
Therefore, the value of a, b, and c is -3, -6, and 5.
Now, substitute the values in the equation of the vertex of a parabola, now, the value of the h and k coordinates can be written as,
h = -b/(2a) = -(-6)/(2 × -3) = -1
k = c - b²/(4a) = 5 - [(-6)²/ (4× -3)] = 8
Hence, the equation of the parabola h(x) = –3x² – 6x + 5 in the vertex form can be written as y = -3(x-1)²+8.
Learn more about Quadratic Equations:
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