Helpppppppppp it’s IXL

Answer:
Step-by-step explanation:
[tex]z^0\times z^{-75}\\\\\mathrm{Apply\:exponent\:rule}:\\\quad \:a^b\cdot \:a^c=a^{b+c}\\\\z^0z^{-75}=z^{0-75}\\\\=z^{-75}[/tex]