Find the standard equation of the circle defined by the equation x^2 + y^2 +8x - 12y + 43 = 0. ANSWERS ATTACHED, due in 2 HOURS, will give Brainliest!

Answer:
Solution: Option C
Step-by-step explanation:
Our goal here is to factor the expression such that it is converted into the circle equation (x - a)² + (y - b)² = r² where r = radius centered at point (a,b).
[tex]x^2\:+\:y^2\:+8x\:-\:12y\:+\:43\:=\:0[/tex] (Factor the expression "x² + 8x")
[tex]x^2+8x = x\left(x+8\right)[/tex] (Factor the expression "y² - 12y")
[tex]\:y^2-12y =y\left(y-12\right)[/tex]
That leaves us with the expression [tex]\left(x-\left(-4\right)\right)^2+\left(y-6\right)^2=3^2[/tex], or in other words [tex](x+4)^2 +(y-6)^2 = 9[/tex]. As you can see our solution is option c.