xiaunat
contestada

Between 10pm and 7:45am, the water level in a swimming pool decreased by 3/8 in. Assuming that the water decreased at a constant rate, how much did the water level drop each hour?

Respuesta :

Answer:

[tex]\frac{1}{26}[/tex] inches

Step-by-step explanation:

In order to solve this problem, we need to create a ratio.

Since we're looking for the rate per hour, we need to find how long it is from 10pm to 7:45am.

10pm + 2 hours = 12 AM

12 AM + 7.75 hours = 7:45 AM

So in total, it's 9.75 hours.

[tex]\frac{3}{8}[/tex] is the same as 0.375.

Our fraction will become [tex]\frac{0.375}{9.75}[/tex], which can simplify down to [tex]\frac{1}{26}[/tex].

Now we can create the proportion:

[tex]\frac{1}{26}=\frac{x}{1}[/tex]

Now we solve for x by cross multiplying.

[tex]1\cdot1=1\\\\1\div26=\frac{1}{26}[/tex]

Hope this helped!