Answer:
One brother says of his younger brother: “Two years ago, I was three times as old as my brother was. In three years’ time, I will be twice as old as my brother.” How old are they each now?
Step-by-step explanation:
Let us suppose two years ago my brother's age was x years
Then, my age was 3x
Three years from now, my brother's age will be (x +2+3) = (x+5) years
And my age will be (3x+2+3) = (3x+5) years
But it is given that i will be twice as old as my brother.
So, 2(x+5)= (3x+5)
or, x= 5 years
So my brother's present age is 5+2= 7 years
And my age is 5*3+2= 17 years
The age of the older brother is 13 and the age of the younger brother is 5.
Two simultaneous equations can be determined from this question:
y = 3x - 2 equation 1
y = 2x + 3 equation 2
Where:
y = older brother's age
x = younger brother's age
Equate equation 1 and equation 2
3x - 2 = 2x + 3
Combine similar terms
3x - 2x = 3 + 2
x = 5
Substitute for x in equation 1
3(5) - 2
15 - 2
y =13
To learn more about simultaneous equations, please check: https://brainly.com/question/25875552
