Stephaniereplogle Stephaniereplogle

24-08-2020
Mathematics

contestada

In a different plan for area codes, the first digit could be any number from 2 through 5, the second digit was either 2, 3, 4, or 5, and the third digit could be any number except 4, 5, or 8. With this plan, how many different area codes are possible?

Respuesta :

jcherry99 jcherry99

24-08-2020

Answer:

Step-by-step explanation:

First digit 2,3,4,5 = 4 different digits.

Second digit 2,3,4,5 = 4 different digits.

Third digit = 1,2,3,6,7,9 = 6 different digits.

Total number of possibilities = 4*4*6 = 96

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