What is the area of a rectangle that is \dfrac1{2} 2 1 ​ start fraction, 1, divided by, 2, end fraction of a meter long and \dfrac38 8 3 ​ start fraction, 3, divided by, 8, end fraction of a meter wide?

Respuesta :

Answer:

[tex]Area = \frac{3}{16} m^2[/tex]

Step-by-step explanation:

Given

Shape: Rectangle

[tex]Length = \frac{1}{2}\ m[/tex]

[tex]Width = \frac{3}{8}\ m[/tex]

Required

Determine the area of the rectangle;

Area is calculated as thus;

[tex]Area = Length * Width[/tex]

Substitute values for Length and Width

[tex]Area = \frac{1}{2} * \frac{3}{8}[/tex]

[tex]Area = \frac{1 * 3}{2 * 8}[/tex]

[tex]Area = \frac{3}{16}[/tex]

Hence, the area of the rectangle is [tex]\frac{3}{16}m^2[/tex]