Answer:
Explanation:
Hello,
In this case, considering the given specific gravity we are to compute the density of the 64% HNO3 solution:
[tex]\rho=1.24*1g/mL=1.24g/mL[/tex]
In such a way, since the given solution of nitric acid is 64 % by mass, we've got:
[tex]\frac{64gHNO_3}{100g\ solution}[/tex]
Thus, by using the previously computed density and the molar mass of HA (90.2 g/mol) we can compute the required molar concentration as follows:
[tex]M=\frac{(100g-64g)HA}{100g\ solution}*\frac{1.24g\ solution }{1mL \ solution}*\frac{1000mL\ solution}{1L\ solution}*\frac{1molHA}{90.2gHA} \\\\M=4.95M[/tex]
Regards.
