Juan added a set of parentheses and a set of brackets in the expression: 15: 3 x 5 + 4 x 8. Juan's expression has a value of 40. What is one way Juan could have written the grouping symbols?

Respuesta :

Answer:

[tex][15: (3 \times 5) + 4] \times 8[/tex]

Step-by-step explanation:

First of all, let us have a look at the rule for solving brackets/parentheses/algebraic operations.

The rule states that the expression must be solved in the following order:

B - Brackets (Innermost parentheses first, then the enclosing brackets are solved)

O - Of (for example 10% of 20)

D - Divide operation

M - Multiplication operation

A - Addition operation

S - Subtraction operation

So, we need to add a set of parentheses i.e. () and a set of brackets i.e. [] in the expression:

[tex]15: 3 \times 5 + 4 \times 8[/tex] such that the result is 40.

Consider the expression: [tex][15: (3 \times 5) + 4] \times 8[/tex]

Let us try to solve the expression using the above rule:

[tex][15: (3 \times 5) + 4] \times 8[/tex]

First of all, the innermost () will be solved:

[tex](3\times 5) = 15[/tex]

Now, the expression becomes:

[tex][15: 15 + 4] \times 8[/tex]

Now, 15:15 will be solved as 1

[tex][1+ 4] \times 8[/tex]

Now, the outer [] will be solved:

[tex]5\times 8 = 40[/tex]

Hence, the correct answer is:

[tex][15: (3 \times 5) + 4] \times 8[/tex]