Answer:
Kinetic energy=1/2 mv^2.
which is 1,000,000,000=1/2×90,000×v^2.
1000000000=45,000v^2.
v^2=222.22.
v=√222.22.
v=14.9~15m/s.
The speed of a 90,000 kg airplane with a kinetic energy of one billion Joules would be 149.07 m/s
Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
Total mechanical energy is s the sum of all the kinetic as well as potential energy stored in the system.
ME = KE + PE
As given in the problem we have to calculate the speed of an airplane with a mass of 90,000 kg and kinetic energy of one billion Joules.
m= 90000 kg
K.E = 1 billion Joules
= 1,000,000,000 Joules
The total kinetic energy
KE = 1/2mv²
By substituting the respective values in the formula of kinetic energy
1,000,000,000 J = 1/2×90000 ×v²
v² = 1,000,000,000 ×2/90000
v² = 22222.222
v =149.07 m/s
Thus, the speed of a 90,000 kg airplane with a kinetic energy of one billion Joules would be 149.07 m/s
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