Answer:
Explanation:
As the 50mL of water are in a big temperature will give heat to the other sample of water.
With the equation:
Q = m*C*T
Where Q is heat, m is mass of the sample, C is specific heat of the sample (4.184J/molK for pure water) and T is temperature in K
We can determine the energy of each sample of water:
Sample 1:
Q = 30.0g*4.184J/molK*282K
Mass is 30.0g because density of water is 1g/mL
Q = 35396.6J
Sample 2:
Q = 50.0g*4.184J/molK*328K
Q = 68617.6J
Total energy is:
Q = 104014.2J
As total mass is 30+50 = 80g, final temperature is:
104014.2J = 80.0g*4.184J*T
310.7K is final temperature of the mixture
