Respuesta :

pukwedgieamerica

Answer:

[tex]t=\frac{2C}{c1-c2}[/tex]

Step-by-step explanation:

[tex]C=\frac{1}{2}t(c1-c2)\\2(C)=2(\frac{1}{2}t(c1-c2))\\2C=t(c1-c2)\\\frac{2C}{c1-c2}=\frac{t(c1-c2)}{c1-c2}\\t=\frac{2C}{c1-c2}[/tex]

devishri1977

Answer:

[tex]t=\frac{2C}{c_{1}-c_{2}}[/tex]

Step-by-step explanation:

[tex]C=\frac{1}{2}*t(c_{1}-C_{2})\\\\[/tex]

Multiply both sides by 2,

[tex]2*C=2*\frac{1}{2}*t*(c_{1}-c_{2})\\\\2C=t*(c_{1}-c_{2})\\\\\frac{2C}{(c_{1}-c_{2})}=t\\\\\\t=\frac{2C}{c_{1}-c_{2}}[/tex]

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