What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged particle as it travels through water (which has an index of refraction of n

Respuesta :

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   [tex]v_w = 2.256 *10^{8} \ m/s[/tex]

B

  [tex]v_e = 2.21 *10^{8} \ m/s[/tex]

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  [tex]n_w = 1.33[/tex]

      The  refractive  index of ethanol is  [tex]n_e = 1.36[/tex]

       

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       [tex]v_w = \frac{c}{n_w }[/tex]

Where  c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

       [tex]v_w = \frac{3.0 *10^{8}}{1.33 }[/tex]

       [tex]v_w = 2.256 *10^{8} \ m/s[/tex]

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            [tex]v_e = \frac{ c}{n_e }[/tex]

  =>       [tex]v_e = \frac{3.0 *10^{8}}{1.36 }[/tex]

=>          [tex]v_e = 2.21 *10^{8} \ m/s[/tex]

Ver imagen okpalawalter8