Respuesta :
We need to find the solution to:
(85 + 83 + 98 + 77 + x) / 5 >= 84 where x is the score in the last test
This is the same as:
(343 + x) / 5 >= 84
Multiplying both sides by 5 we get
343 + x >= 420
Subtracting 343 from both sides we get
x >= 77
There for the student must get a score of at least 77 on the last tests.
(85 + 83 + 98 + 77 + x) / 5 >= 84 where x is the score in the last test
This is the same as:
(343 + x) / 5 >= 84
Multiplying both sides by 5 we get
343 + x >= 420
Subtracting 343 from both sides we get
x >= 77
There for the student must get a score of at least 77 on the last tests.
She should score more than 77 on the fifth quiz to have an average of at least 84 .
What is average?
The average is the middle value of a set of numbers. This isn't to be confused with the median, which is the middle of a set of numbers. The average is the middle value of the numbers. If you need to find the average of a set of numbers, you add them all together and divide by the amount of numbers.
Formula of average:
[tex]Average = \frac{Sum of terms }{Number of terms }[/tex]
According to the question
A student has scores on four quizzes : 85,83,98,77
she score on the fifth quiz to have an average of at least 84
Let fifth quiz score = x
By using formula of average:
[tex]Average = \frac{Sum of terms }{Number of terms }[/tex]
As average should be at least 84
[tex]84 < \frac{85+83+98+77+x }{5 }[/tex]
420 < 343+x
420 - 343 < x
77< x
Therefore,
x should be greater than 77 .
Hence, she should score more than 77 on the fifth quiz to have an average of at least 84 .
To know more about average here:
https://brainly.com/question/24057012
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