Answer:
[tex]\bold{4r^3 (6-\pi)}[/tex]
Step-by-step explanation:
Let us try to visualize the given situation in the form of 2 Dimensional image as shown in the attached diagram.
Let the Diameter of spherical balls be D.
As the spherical balls are completely fit in the rectangular box, the sides of box become:
[tex]D \times D\times (3 \times D)[/tex] OR [tex]D\times D\times 3D[/tex]
We know that Diameter is twice of radius.
Therefore [tex]D = 2r[/tex]
So, the dimensions of rectangular box becomes:
[tex]2r \times 2r \times 6r[/tex]
Volume of a rectangular box is given as:
[tex]V = Length \times Width \times Height\\\Rightarrow V = 2r\times 2r\times 6r = \bold{24r^3}[/tex]
Now, let us find out the volume of each spherical ball.
Volume of a sphere with radius 'r' is given as:
[tex]V_{sphere} = \dfrac{4}{3}\pi r^3[/tex]
Volume of 3 spheres = [tex]3\times \frac{4}{3}\pi r^3 =4\pi r^3[/tex]
Now, the volume of space between the balls and rectangular box is = Volume of rectangular box - Volume of 3 balls
[tex]24r^3 - 4\pi r^3\\\Rightarrow \bold{4r^3 (6-\pi)}[/tex]
