Answer:
The daughter nuclides of these two decay processes are [tex]^{192}_{78}Pt [/tex] and [tex]^{192}_{76}Os[/tex].
Explanation:
The beta emission is represented by:
A = (Z + 1) + (n - 1) = is invariant
n: neutron
p: proton
[tex]^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y[/tex]
Hence, the daughter nuclide of the beta emission of Ir-192 is:
[tex]^{192}_{77}Ir \rightarrow ^{192}_{78}Pt[/tex]
Now, electron capture is represented by:
A = (Z - 1) + (n + 1) = is invariant
[tex]^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y[/tex]
Then, the daughter nuclide of the electron capture of Ir-192 is:
[tex]^{192}_{77}Ir \rightarrow ^{192}_{76}Os[/tex]
Therefore, the daughter nuclides of these two decay processes are [tex]^{192}_{78}Pt [/tex] and [tex]^{192}_{76}Os[/tex].
I hope it helps you!
