Answer:
49 and 118
Step-by-step explanation:
Let the two numbers be x and y
x+y = 167
y = 3x-29
Substitute into the first equation
x+ 3x-29 = 167
Combine like terms
4x - 29 = 167
add 29 to each side
4x = 167+29
4x = 196
Divide by 4
4x/4 = 196/4
x = 49
x+y = 167
49+y = 167
y = 167-49
y =118
Answer:
[tex]\Huge \boxed{\mathrm{49 \ and \ 118}}[/tex]
Step-by-step explanation:
Let the first number be [tex]x[/tex]
Let the second number be [tex]y[/tex]
[tex]x+y=167[/tex]
[tex]y=3x-29[/tex]
Applying substitution method.
[tex]x+3x-29=167[/tex]
Combining like terms.
[tex]4x-29=167[/tex]
Adding 29 to both sides.
[tex]4x=196[/tex]
Dividing both sides by 4.
[tex]x=49[/tex]
Substituting x = 49 for the second equation.
[tex]y=3(49)-29[/tex]
Multiplying the numbers.
[tex]y=147-29[/tex]
Subtracting.
[tex]y=118[/tex]
The two required numbers are 49 and 118.
