Answer:
The answer is "33.95 [tex]\bold{ \frac{kj}{mol}}\\[/tex]".
Explanation:
Formula:
[tex]\bigtriangleup G_0= -R \times T l_n \times K_{eq}\\[/tex]
where
[tex]K_{eq} = \text{equilibrium constant}\\[/tex]
Given value:
[tex]T =35^{\circ} C\\[/tex]
convert temperature celsius (°C) to Kelvin (K):
[tex]= (273+45) \ kelvin \\\\= 318 \ Kelvin \\\\= 318 \ K[/tex]
[tex]R = 8.314 \ \ \frac{J}{ mol \cdot K}[/tex]
[tex]\bigtriangleup G_0= -(8.314 ) \times 31.8 \times l_n (2.65\times 10^{-6})\\[/tex]
[tex]=-(8.314 ) \times 31.8T l_n \times (2.65\times 10^{-6})\\\\[/tex]
After solving the value it will give:
= 33.95 [tex]\bold{ \frac{kj}{mol}}\\[/tex]
